![]() Therefore, the transmitted intensity is 500 W / m 2. When unpolarized light passes through a polarizer, the intensity is cut in half. What is the intensity of the light transmitted by the first polarizer? (a) Unpolarized light, with an intensity of 1000 W/m 2 is incident on the first polarizer. This problem deals with light passing through a succession of polarizers as indicated in the sketch: The easiest one to use here is the motional emf equation: Now we can apply an induced emf equation. ![]() (c) What is the value of the constant velocity v of the loop? Fortunately, it's easy because we know both the current and resistance in the loop, so we can apply the familiar equation from circuits: (b) What is the induced emf that is generated in the loop and causes the current I to flow?Īlthough this is an induced emf problem, there isn't enough information here to solve for the induced emf using an induced emf equation. The first picture, with current counter-clockwise, is correct. Current flowing counter-clockwise around the loop generates a magentic field out of the page (the right-hand rule can be used to determine this - if you curl your fingers on your right hand in the direction of the current, your thumb points in the direction of the field produced by that current). Lenz's law says that if the magnetic flux through the loop is increasing into the page, the loop will set up a flux out of the page to try to cancel the change. The loop is moving into the field, which points into the page. (a) Which way will the induced current flow in the loop? An induced current of I = 0.043 amperes is flowing around the loop. The magnetic field is perpendicular to the plane of the loop and into the page as shown in the sketch. ![]() A square loop of wire with sides of length L = 0.17 m and total resistance R = 50 ohms is moving with constant velocity v into a region of constant magnetic field B = 0.76 T.
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